0=10x^2+62x+12

Solution for 0=10x^2+62x+12 equation:

0=10x^2+62x+12

We move all terms to the left:

0-(10x^2+62x+12)=0

We add all the numbers together, and all the variables

-(10x^2+62x+12)=0

We get rid of parentheses

-10x^2-62x-12=0

a = -10; b = -62; c = -12;
Δ = b2-4ac
Δ = -622-4·(-10)·(-12)
Δ = 3364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3364}=58$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-62)-58}{2*-10}=\frac{4}{-20}
=-1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-62)+58}{2*-10}=\frac{120}{-20}
=-6
$